(2+4+6+8+.+2002)—(1+3+5+7+.+2003)简便运算的步骤是?

问题描述:

(2+4+6+8+.+2002)—(1+3+5+7+.+2003)简便运算的步骤是?

(2+4+6+8+.+2002)—(1+3+5+7+.+2003) =(2-1)+(4-3)+(6-5)+(8-7)+……+(2002-2001)-2003 =1x1001-2003 =-1002
采纳哦