已知x+2y-3=0,试求x^2+4y^2+4xy+3x+6y-8的值
问题描述:
已知x+2y-3=0,试求x^2+4y^2+4xy+3x+6y-8的值
答
x+2y-3=0,则x+2y=3
x^2+4y^2+4xy+3x+6y-8
=(x+2y)方+3(x+2y)-8
=3方+3*3-8=9+9-8=10