求因式分解 (x+2)^3-1 (3a-b)(x-y)(a+3b)(x-y) (x+2)(x+4)+x^2-4 a^2b^2+2b-1
问题描述：
求因式分解 (x+2)^3-1 (3a-b)(x-y)(a+3b)(x-y) (x+2)(x+4)+x^2-4 a^2b^2+2b-1
答
(x+2)^3-1=[﹙x＋2﹚－1][﹙x＋2﹚²＋﹙x＋2﹚＋1]=﹙x＋2－1﹚﹙x²＋4x＋4＋x＋2＋1﹚=﹙x＋1﹚﹙x²＋5x＋7﹚(3a-b)(x-y)＋(a+3b)(x-y) (是这个吗?)=(x-y)[(3a-b)＋(a+3b)]=(x-y)﹙4a＋2b﹚=2(x-y)...