用余式定理来因式分解:6x^4+5x^3-38x^2+5x+6

问题描述:

用余式定理来因式分解:6x^4+5x^3-38x^2+5x+6

(x - 2)(2x - 1)(3x + 1)(x + 3)

6x^4+5x^3-38x^2+5x+6=(6x^4+5x^3-39x^2)+(x^2+5x+6)=x^2(6x^2+5x-39)+(x+2)(x+3)=x^2(x+3)(6x-13)+(x+2)(x+3)=(x+3)(6x^3-13x^2+x+2)=(x+3)(6x^3-13x^2+2x-x+2)=(x+3)[x(6x^2-13x+2)-(x-2)]=(x+3)[x(x-2)(6x-1)-(x-...