log2(底)(x+1)(真)-log2(底)(2x-1)(真)=1log2(底)(x^2-x)=log2(底)2(x-2)lg^2x+lgx^2-3=01/(5-lgx)+2/(1+lgx)=1
问题描述:
log2(底)(x+1)(真)-log2(底)(2x-1)(真)=1
log2(底)(x^2-x)=log2(底)2(x-2)
lg^2x+lgx^2-3=0
1/(5-lgx)+2/(1+lgx)=1
答
log2(底)(x^2-x)=log2(底)2(x-2)
x^2-x=2(x-2)
x^2-3x+4=0
△=9-16