(a^2-3a)^2-14(a^2-3a)+40 十字相乘法解
问题描述：
(a^2-3a)^2-14(a^2-3a)+40 十字相乘法解
答
(a²-3a)²-14(a²-3a)+40
=[(a²-3a)-4][(a²-3a)-10]
=(a²-3a-4)(a²-3a-10)
=(a+1)(a-4)(a+2)(a-5)
答
(a^2-3a)^2-14(a^2-3a)+40
=[(a²-3a)-4]*[(a²-3a)-10]
=(a²-3a-4)*(a²-3a-10)
=(a+1)(a-4)(a+2)(a-5)