X(x+3)分之一+(X+3)(X+6)分之一+(X+6)(X+9)分之一=2x+18分之三快
问题描述:
X(x+3)分之一+(X+3)(X+6)分之一+(X+6)(X+9)分之一=2x+18分之三
快
答
公式:1/n(n+3)=1/3[1/n-1/(n+3)]
1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=3/(2x+18)
1/3[1/x-1/(x+3)+1/(x+3)-1/(x+6)+1/(x+6)-1/(x+9)]=3/(2x+18)
1/3[1/x-1/(x+9)]=3/2(x+9)
2(x+9)-2x=9x
9x=18
x=2
答
1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=3/2(x+9)(1/3)×[3/x(x+3)+3/(x+3)(x+6)+3/(x+6)(x+9)]=3/2(x+9)(1/3)[(1/x-1/(x+3)+1/(x+3)-1/(x+6)+1/(x+6)-1/(x+9)]=3/2(x+9)(1/3)[1/x-1/(x+9)]=3/2(x+9)1/...