设a=0.1的0.9次方 b=3.2的0.4次方 c=log(5.2的0.6次方),比较大小

问题描述:

设a=0.1的0.9次方 b=3.2的0.4次方 c=log(5.2的0.6次方),比较大小

a=0.1^0.9 lga=0.9*lg0.1=-0.9b=3.2^0.4 lgb=0.4lg3.2>0 b>1
c=log(5.2 0.6)b>a>c

a=0.1^0.9b=3.2^0.4>1
c=log5.2(0.6)故有b>a>c