复数的乘法与除法若n为正整数,求(1+i/1-i)^2n
问题描述：
复数的乘法与除法
若n为正整数,求(1+i/1-i)^2n
答
(1+i/1-i)^2n
=[(1+i)²/2)^2n
=(i)^2n
答
1+i/1-i
=(1+i)(1+i)/[(1+i)(1-i)]
=2i/2
=i
(1+i/1-i)^2n
=i^2n
=（i²）^n
=(-1)^n
(1) n是奇数,原式=-1
(2) n是偶数,原式=1