nxn十n-1二0则nxnxn十2nx n十2008

分类: 作业答案 • 2022-09-03 08:35:32

问题描述：

答

n×n=-n+1
n×n×n=n×(-n+1)=-n×n+n
∴ n×n×n+2n×n+2008
=-n×n+n+2n×n+2008
=n×n+n+2008
=-n+1+n+2008
=2009