2x^2*x^3+x*(-3x^4)(2a^2b)^2*3b-4a^4b^3
问题描述:
2x^2*x^3+x*(-3x^4)
(2a^2b)^2*3b-4a^4b^3
答
2x^2*x^3+x*(-3x^4)
=2x^(2+3)-3x^(1+4)
=2x^5-3x^5
=-x^5
(2a^2b)^2*3b-4a^4b^3
=4a^4b^2*3b-4a^4b^3
=4a^4b^3-4a^4b^3
=0