a degree 3 polynomial that has zeros -1,1 and 6 and in which the coefficient of x^2 is -12.
问题描述：
a degree 3 polynomial that has zeros -1,1 and 6 and in which the coefficient of x^2 is -12.
答
有三个零点,即(x+1)(x-1)(x+6)=0,乘开之后是x^3+6x^2-x-6 未完全正确,因为还有限制条件--二次项系数是12,所以还要乘一个二, 2(x+1)(x-1)(x+6)=0才是正确答案
答
一个3次多项式有零点-1,1和6,且x的平方项的系数是-12