因式分解x^2+4x+3 a^2+7a+10 y^2-7y+12 q^2-6q+8
问题描述：
因式分解x^2+4x+3 a^2+7a+10 y^2-7y+12 q^2-6q+8
答
x^2+4x+3
=(x+3)(x+1)
a^2+7a+10
=(a+5)(a+2)
y^2-7y+12
=(y-3)(y-4)
q^2-6q+8
=(q-2)(q-4)
答
x^2+4x+3
=(X+3)(x+1)
a^2+7a+10
=(a+2)(a+5)
y^2-7y+12
=(y-3)(y-4)
q^2-6q+8
=(q-2)(q-4)