x-48=5/9x-20怎么解?
问题描述:
x-48=5/9x-20怎么解?
答
原式=
X-48+20=5/9X
X-28=5/9X
9X(X-28)=5
9X方-252X+5=0
然后用求根公式就可以了。。X=2a分之负B加减根号下B方减4AC
答
4/9X=28
X=63
当X=0时,等式不成立
当X不等于0时,等式两边同时乘以9X
答
两边同乘以9X
答
x-48=5/9x-20
x-5x/9=-20+48
4x/9=24
x=54
答
x-48=5/9x-20
x-5/9x=48-20
x=28÷4/9
x=63
答
x-48=5/9x-20
x-5/9x=48-20
4/9x=28
x=63
答
x-48=5/9x-20
x-5/9x=48-20
4/9x=28
x=63