若lim[2n+(an^2+2n+1)/(bn+1)=1,则a+b

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若lim[2n+(an^2+2n+1)/(bn+1)=1,则a+b

若lim(2n (an^2-2n 1)/(bn 2))=1 求a/b的值 纠正一下:你lim(2n 1)/(bn 2))=1 上下除以2 则lim(2 1/n)/(b 2/n)=1 则

表述好像有点不清楚

lim(n->inf) [2n + (an² + 2n + 1) / (bn + 1)] = 1lim (2bn² + an² + 4n + 1) / (bn + 1) = 1lim [(2b + a)n² + 4n + 1] / (bn + 1) = 12b + a = 0,∵极限趋向常数,分子和分母的最高次方相同,...