用配方法解2个方程(1-y)(3y-2)=y(y-3)(1-y)(3y-2)=y(y-3)2/3x^2-4/9x-1/3=0
问题描述:
用配方法解2个方程(1-y)(3y-2)=y(y-3)
(1-y)(3y-2)=y(y-3)
2/3x^2-4/9x-1/3=0
答
(1)展开后,整理得到:2y^2-4y+1=02(y^2-2y+1)-2+1=02(y-1)^2=1(y-1)^2=0.5y-1=正负2分之根号2y=1+正负2分之根号2(2)通分之后得到:3x^2+4x-6=03(x^2+0.75x+9/64)-6-27/64=0(x-3/8)^2=137/64x-3/8=正负根号137/8x...