(x-2)(x-3)=12这道题怎么用分解因式法解

分类: 作业答案 • 2022-08-01 10:45:00

问题描述：

答

(x-2)(x-3)=12
x^2-5x+6=12
x^2-5x-6=0
(x+1)(x-6)=0
x=-1或x=6

答

(x-2)(x-3) = 12
x² - 5x + 6 = 12
x² - 5x - 6 = 0
(x + 1)(x - 6) = 0
x = 6 或 x = -1