三角函数方程求解2arctan(167.5/x)+arctan[167.5/(950-x)]=180

题目似乎应该是“2arctan(167.5/x)+arctan[167.5/(950-x)]=180°”.tan[2arctan(167.5/x)]+tan{arctan[167.5/(950-x)]}=0,335x/[x^2-167.5^2]+167.5/(950-x)=0,335x(950-x)+167.5(x^2-167.5^2)=0,1900x-2x^2+x^2-167...