已知函数f (x)=x|x-a|-In(x+1)(1)当a =0时,求函数f (x)的单调区间..(2)当a =-1时,若全部x 都属于[0,正无穷),f (x)小于等于(k +1)x的平方恒成立,求实数k 最小值.要具体过程,
已知函数f (x)=x|x-a|-In(x+1)
(1)当a =0时,求函数f (x)的单调区间..(2)当a =-1时,若全部x 都属于[0,正无穷),f (x)小于等于(k +1)x的平方恒成立,求实数k 最小值.要具体过程,
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2010-09-16 19:58
liangxiaoruyue
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F'(X)= A(X +1)(XA),
G之(X)= A(2X-1 +1)
若f(x)在x = a到检查的最大值,则f''(A)= A(2A-1 +1)一个(+1)所以-1
(1)a=0f(x)=x*|x|-ln(x+1)定义域是(-1,+∞)当-1=02kx>=1-1/(x+1)2kx>=x/(x+1)∵x>=0∴k>=1/[2(x+1)]x=0,1/[2(x+1)]有最大值=1/2∴k>=1/2实数k 最小值=1/2如果您认可我的回答,请及时点击右下角的【满意】按钮或点击“...