已知三元一次方程组13x+5y+9z=18.5,4x+2y+3z=6.2,6x+5y+2z=8的解为x=0.5,y=0.6,z=1,求
问题描述：
已知三元一次方程组13x+5y+9z=18.5,4x+2y+3z=6.2,6x+5y+2z=8的解为x=0.5,y=0.6,z=1,求
答
楼上正解。过程我就不讲了，其实方法很简单，就是利用方程组两两相加或相减，消去一个未知数然后联立就可以了。
答
木有分，路过。
答
13x+5y+9z=18.5················①4x+2y+3z=6.2···················②6x+5y+2z=8····················③①-③得 7x+7z=10.5···············...