1/5(lg32+log(4)(16)+6lg1/2)+1/5lg1/5解答过程

问题描述:

1/5(lg32+log(4)(16)+6lg1/2)+1/5lg1/5解答过程

log(4)(16)=2
lg32=lg2^5=5lg2
lg1/2=-lg2,lg1/5=-lg5
==1/5(-lg2+2)-1/5lg5=-1/5(lg2+lg5)+0.4
=-0.2*lg10+0.4=0.2