已知13X^2-6XY+Y^2-4X+1=0,求(XY-X^2)^5的值.
问题描述：
已知13X^2-6XY+Y^2-4X+1=0,求(XY-X^2)^5的值.
答
13x^2-6xy+y^2-4x+1=0 9x^2-6xy+y^2+4x^2-4x+1=0 (3x-y)^2+(2x-1)^2=0 3x-y=0,2x-1=0,x=0.5 y=3*0.5=1.5 (xy-x^2)^5=(0.5*1.5-0.5^2)^5 =(0.5(1.5-0.5))^5 =0.5^5 =1/32