sin220°+cos210°+tan315°+2cos300°等于多少,

问题描述:

sin220°+cos210°+tan315°+2cos300°等于多少,

sin220°=sin(-40)° cos210°=cos(-30)°=-cos30°=-√3/2 tan315°=tan(-45)°=-tan45°=-1 cos300°=cos60°=0.5 sin220°+cos210°+tan315°+2cos300° =sin(-40)°-√3/2-1+2×0.5 =-sin40°-√3/2