求值:2sin20(单位是度,以下也是)+cos10+tan20sin10
问题描述:
求值:2sin20(单位是度,以下也是)+cos10+tan20sin10
我的提问已解答,如何删除?
答
2sin20+cos10+tan20*sin10
=2sin20+(cos10+sin20sin10/cos20)(括号内通分)
=2sin20+cos10/cos20(再通分)
=(sin40+cos10)/cos20
=(sin40+sin80)/cos20(和差化积)
=2sin60cos20/cos20
=2sin60
=√3