如果(x-2)(x-k)=x.x+px-6则k=___p=____

问题描述:

如果(x-2)(x-k)=x.x+px-6则k=___p=____

(x-2)(x-k) = x.x - 2x - kx + 2k
=x.x + (-2-k).x + 2k
所以,-2-k =p,2k= -6 得出:k= -3,p=1