x减一分之x平方减2x减3大于等于x的解集
问题描述：
x减一分之x平方减2x减3大于等于x的解集
答
答案为1＞x≥-3。解法是把右边x移项同分。记得分母不能取1
答
(x²－2x－3)/(x－1)≥x
(x²－2x－3)/(x－1)－(x²－x)/(x－1)≥0
(－x－3)/(x－1)≥0
(x＋3)/(x－1)≤0
－3≤x解集为{x|－3≤x
答
(x2-2x-3)/(x-1)>=x
[(x2-2x-3)-x(x-1)]/(x-1)>=0
(-x-3)/(x-1)>=0
(x+3)/(x-1)
答
(x^2-2x-3)/(x-1)＞x
(x^2-2x-3)/(x-1)-x＞0
(-2x-2)/(x-1)＞0
(2x+2)*(x-1)＞0
(x+1)*(x-1)＞0
所以x＞1或者x＜-1