1200/x-1200/(x+2)=30

问题描述:

1200/x-1200/(x+2)=30

1200/x-1200/(x+2)=30
40(x+2)-40x=x(x+2)
40x+80-40x=x²+2x
x²+2x-80=0
(x+10)(x-8)=0
x1=-10,x2=8