初二一元二次方程一道————————————————————————x+2/x-2 +x²-4/3x²-5x-2=1答案【x1=0,x2=-12】要详细过程

100=a1(1-q^100)/(1-q)=600
q^50=2
则a1(1-4)/(1-q)=600
a1/(1-q)=-200
S50a1(1-q^50)/(1-q)
=-200*(1-2)
=200

(x+2)/(x-2)+(x+2)(x-2)/(3x+1)(x-2)=1
(x+2)/(x-2)+(x+2)/(3x+1)=1
两边乘(x-2)(3x+1)
3x²+7x+2+x²-4=3x²-5x-2
x²+12x=0
x(x+12)0
x=0,x=-12