测得三极管的三个电极的静态电流分别为IB=0.06mA,IE=3.66mA,IC=3.6mA.则该管的β为()
问题描述:
测得三极管的三个电极的静态电流分别为IB=0.06mA,IE=3.66mA,IC=3.6mA.则该管的β为()
答
β=IC/IB=60
测得三极管的三个电极的静态电流分别为IB=0.06mA,IE=3.66mA,IC=3.6mA.则该管的β为()
β=IC/IB=60