导数y=log2x(3-x),x=1帮忙算下求y=log2x(3-x) |x=1的导数
问题描述:
导数y=log2x(3-x),x=1
帮忙算下
求y=log2x(3-x) |x=1的导数
答
本题题意有二:若是y = log₂【x(3-x)】= ln【x(3-x)】/ln2= 【lnx + ln(3-x)】/ln2dy/dx = 1/(xln2) - 1/(3-x)ln2若 x = 1dy/dx|(x=1) = 1/ln2 - 1/2ln2 = 1/2ln2 (或 1/ln4)若是y = log(2x)【3-x】= ln(3-x...