帮忙解决下这个高数题已知ln(x+2y)=sin(xy)+1确定函数y=y(x),则y'(0)=答案是(e*e-2)/4

ln(x+2y)=sin(xy)+1对x求导1/(x+2y)*(x+2y)'=cos(xy)*(xy)'+0(1+2y')/(x+2y)=cos(xy)*(y+x*y')x=0则ln(0+2y)=0+1=12y=ey=e/2代入整理y'(0)=[1-e(1+e)/2*cos(e/2)]/[(1+e)cos(e/2)-2]