问几道初二的因式分解（要有过程）1.18X的N+1次方-24X的N次方2.已知A+B=3,A²B+AB²=1,则AB=3.X(X-Y)(A-B)-Y(Y-X)(B-A)4.6X(X-Y)²+3（Y-X）³5.4(M+N)²-9（M-N)²

1, 18X的N+1次方-24X的N次方 6X的N次方(3x-4)
2, A²B+AB²=1, 则AB(A+B)=1 因为A+B=3 所以 AB=1/3
3， X(X-Y)(A-B)-Y(Y-X)(B-A)=X(X-Y)(A-B)-Y(X-Y)(A-B)=(X-Y)²(A-B)
4， 6X(X-Y)²+3（Y-X）³= 6X(X-Y)²-3（X-Y）³=3(X-Y)²（2x-3x+3Y)=3(X-Y)²（3Y-X)
5, 4(M+N)²-9（M-N)²=［2(M+N)］²-［3(M-N)］²=(2M+2N+3M-3N)(2M+2N-3M+3N)=
(5M-N)(5N-M)

1.6x^n(3x-4)
2.A²B+AB²=1=AB(A+B)
AB=1/3
3.(X-Y)^2(A-B)
4.6X(X-Y)²+3（Y-X）³
=6X(X-Y)²-3（X-Y）³
=3(X-Y)²(2X-X+Y)
=3(X-Y)²(X+Y)
5.4(M+N)²-9（M-N)²
=[2((M+N)]²-[3((M-N)]²
=[2(M+N)+3((M-N)][2(M+N)-3((M-N)]
=(5M-N)(5N-M)

1.6x^n(3x-4)2.A²B+AB²=AB（A+B）=1 AB=1/33.原式=x(x-y(A-B)-y(x-y)(A-B)=(x-y)²（A-B)4.原式=6x(x-y)²-3（x-y)^3=(x-y)^2(6x-3(x-y))=3(x-y)^2(x+y)5.(2(M+N)+3(M-N))(2(M+N)-3(M-N))=(5M-N)(...

1、6X^N(3X-4)
2、AB=1/3
3、(X-Y)^2(A-B)
4、3（X+Y）（X-Y）^2
5、-（5M-N）（M-5N）