the minimum value of y=x^3-x on the interval (0,1)how to find the minimum and maximum values for the function like:y=ax^3-bx?

分类: 作业答案 • 2022-07-06 09:00:54

问题描述：

the minimum value of y=x^3-x on the interval (0,1)
how to find the minimum and maximum values for the function like:y=ax^3-bx?

答

the most simple method is to find the derivative of the function.
y'= 3x^2-1
thus whenever x∈(0,sqrt(1/3)) the derivative y'(x)