1.8*[6又5/12/16+3/8*(9-2又7/120]/2又3/4这道题应该怎么计算?写清楚因为算式长

1.8×[(77/12)/16+(3/8)×(9-247/120)]/(11/4)=1.8×[77/(12×16)+(3/8)×(833/120)]/(11/4)=(1又4/5)×(77/192+833/320)×(4/11)=(9/5)×(385/960+2499/960)×(4/11)=(9/5)×(721/240)×(4/11)=2163/1100=1又1063/1...