化简求值 [(x+2y)(x-2y)-(2x-y)ˆ2+(3x+y)(2x+5y)]÷(-1/2x),其中x=3,y=1.
问题描述:
化简求值 [(x+2y)(x-2y)-(2x-y)ˆ2+(3x+y)(2x+5y)]÷(-1/2x),其中x=3,y=1.
答
=[x^2-4y^2-2x^2+4xy-y^2+6x^2+17xy+5y^2]*(-2x)
=[5x^2+21xy]*(-2x)
=-2x^2(5x+21y)
=-18*36
=-648不对吧=[x^2-4y^2-4x^2+4xy-y^2+6x^2+17xy+5y^2]*(-2x)=[3x^2+21xy]*(-2x)=-2x^2(3x+21y)=-6x^2(x+7y)=-6*9*10=-540(sorry)