【SOS!】两道初三二次根式的计算题,明天要交的!

问题描述:

【SOS!】两道初三二次根式的计算题,明天要交的!
1/根号5+2-(根号3-2)^6+根号20
根号18-(根号3+1)^6+(-1)^2

(1) =根号5/5+2-((根号3-)^2)^3+2*根号5
=11*根号5/5+2-(3-4*根号3+4)^3
=11*根号5/5+2-(7-4*根号3)^2(7-4*根号3)
=11*根号5/5+2-(679-392*根号3-388*根号3+672)
=11*根号5/5+2-1430+780*根号3
=11*根号5/5+780*根号3-1428
(2) =3*根号2-((根号3+1)^2)^3+1
=3*根号2-(4+2*根号3)^2(4+2*根号3)+1
=3*根号2-108-120*根号3+1
=3*根号2-120*根号3-207