裂项法1/2X5+1/5x8+1/8x11.1/2009x2012=?

问题描述:

裂项法1/2X5+1/5x8+1/8x11.1/2009x2012=?

1/2X5 =1/3(1/2-1/5)
1/5x8=1/3(1/5-1/8)
所以原式=1/3(1/2-1/5+1/5-1/8+.+1/2009-1/2012)
=1/3(1/2-1/2012)
=1/3x1005/2012
=335/2012