求 x^3-6x^2+3x+10 最好能告诉我此类问题的方法 不要只写过程

T

x^3-6x^2+3x+10
=x3+1-3(2x2-x-3)
=(x+1)(x2-x+1)-3(x+1)(2x-3)
=(x+1)(x2-7x+10)
=(x+1)(x-2)(x-5)

找公共项,然后提取公因式,再化简就差不多了
x^3-6x^2+3x+10
=x^3+1-3(2x^2-x-3)
=(x+1)(x^2-x+1)-3(x+1)(2x-3)
=(x+1)(x2^-7x+10)
=(x+1)(x-2)(x-5)