(p-2q)^2-2(p+2q)(p+3q)+(p+3q)^2
问题描述:
(p-2q)^2-2(p+2q)(p+3q)+(p+3q)^2
答
解原式=(p²-4pq+4q²)-2(p²+5pq+6q²)+(p²+6pq+9q²)=(p²-2p²+p²)+(-4pq-10pq+6pq)+(4q²-12q²+9q²)=-8pq+q²
(p-2q)^2-2(p+2q)(p+3q)+(p+3q)^2
解原式=(p²-4pq+4q²)-2(p²+5pq+6q²)+(p²+6pq+9q²)=(p²-2p²+p²)+(-4pq-10pq+6pq)+(4q²-12q²+9q²)=-8pq+q²