find three consecutive integers such that twice the least integer is 12 more than the greatest
问题描述：
find three consecutive integers such that twice the least integer is 12 more than the greatest
答
Find three consecutive integers such that twice the least integer is 12 more than the greatest.
找到3个连续的整数,例如最小整数的两倍比最大的大12.
回答：设三个数为 a,a+1,a+2
则 2a - 12 = a + 2
a = 14
即,这三个数是 14,15,16
谢谢o(∩_∩)o