2y²+4y=y+2 (x-2)²=(2x+3)² (4x-1)(5x+7)=0 3x(x-1)=2-2x
问题描述:
2y²+4y=y+2 (x-2)²=(2x+3)² (4x-1)(5x+7)=0 3x(x-1)=2-2x
答
1.
2y²+4y=y+2
2y(y+2)=y+2
(y+2)(2y-1)=0
所以y=-2或y=1/2
2.
(x-2)²=(2x+3)²
(x-2)²-(2x+3)²=0
(x-2+2x+3)(x-2-2x-3)=0
(3x+1)(-x-5)=0
所以x=-1/3或x=-5
3.
(4x-1)(5x+7)=0
所以x=1/4或x=-7/5
4.
3x(x-1)=2-2x
3x(x-1)=-2(x-1)
(x-1)(3x+2)=0
所以x=1或x=-2/3
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