ab^2/2c^除以-3a^2b^2/4cd=
问题描述:
ab^2/2c^除以-3a^2b^2/4cd=
答
ab^2/2c^除以-3a^2b^2/4cd
=-ab^2/(2c^2)×[4cd/(3a^2b^2)]
=-2d/(3ac)