1.求函数y=sin(2x-π/3)的对称中心
问题描述：
1.求函数y=sin(2x-π/3)的对称中心
2.求函数y=sin(π/3-2x)的单调递增区间、对称轴
答
y=sin(2x-π/3)= 2sin(x-π/6) x-π/6=Kπ+π/2 x=Kπ+2/3π 对称轴y=sin(π/3-2x)= 2sin(π/6-x) π/6-x=Kπ+π/2 x=-Kπ-1/3π 对称轴单调递增区间：2Kπ-π/2《π/3-2x《2Kπ+π/2 -2Kπ+π/2》2x-...