[-2009又 5/6]+[-2007又 2/3]+5017又 3/4+[-1又 1/2]用拆除法算怎么算?
问题描述:
[-2009又 5/6]+[-2007又 2/3]+5017又 3/4+[-1又 1/2]用拆除法算怎么算?
答
原式=(-2010+1/6)+(-2008+1/3)+5018-1/4+(-2+1/2)=998又3/4
[-2009又 5/6]+[-2007又 2/3]+5017又 3/4+[-1又 1/2]用拆除法算怎么算?
原式=(-2010+1/6)+(-2008+1/3)+5018-1/4+(-2+1/2)=998又3/4