x＜y＜z,k为整数且1/x+1/y+1/z=k,试求x、y、z的值
问题描述：
x＜y＜z,k为整数且1/x+1/y+1/z=k,试求x、y、z的值
答
x,y,z也都是整数吧?1/(-1)+1/(-2)+1/(-3)≤1/x+1/y+1/z ≤1/1+1/2+1/3,且1/x+1/y+1/z为整数即-11/6≤1/x+1/y+1/z ≤11/6,且1/x+1/y+1/z为整数∴1/x+1/y+1/z可取的值为-1,0,1当k=-1时,x=-2,y=-3,z=-6当k=1时,x=2,y=3,...