求值域 y=3+2cos(2x-π/3) x∈[-π/2,π/2] 【有具体过程的.
问题描述：
求值域 y=3+2cos(2x-π/3) x∈[-π/2,π/2] 【有具体过程的.
答
x∈[-π/2,π/2] ,所以(2x-π/3) ∈[-4π/3,2π/3] ∴f（x）∈[5/2,3] ,可是你的答案错了= =
求值域 y=3+2cos(2x-π/3) x∈[-π/2,π/2] 【有具体过程的.
x∈[-π/2,π/2] ,所以(2x-π/3) ∈[-4π/3,2π/3] ∴f（x）∈[5/2,3] ,可是你的答案错了= =