1/42+1/56+1/72+1/90+1/110+1/132=?
问题描述:
1/42+1/56+1/72+1/90+1/110+1/132=?
答
1/42+1/56+1/72+1/90+1/110+1/132=?
=1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10+1/10-1/11+1/11-1/12
=1/6-1/12
=1/12