2t(3-t)=6怎么解
问题描述：
2t(3-t)=6怎么解
答
t(3-t)=3
0 = 3 + t^2 - 3t
(t-3/2)^2 - 9/4 + 3 =0
(t-3/2)^2 + 3/4 = 0
(t-3/2)^2 = - 3/4 = (-1) * 3/4 = i^2 * (根号3 /2)^2
t-3/2 = ±根号3 i /2
t= 3/2 ± i(根号3)/2
i是虚数单位.这不是实数解,这方程没有实数解.