ax^2+3x^2-4a-12 分解因式如题还有x^2+a^2-bx-ab+2ax和x^2-4x+4-3x+6和x^4-2x^2+x^2y-y+1

ax^2+3x^2-4a-12
a(x^2-4)+3(x^2-4)
=(a+3)(x+2)(x-2)
x^2+a^2-bx-ab+2ax
=(x+a)^2-b(x+a)
=(x+a)(x+a-b)
x^2-4x+4-3x+6
=x^2-7x+10
=(x-5)(x-2)
x^4-2x^2+x^2y-y+1
=x^4-x^2-x^2+x^2y-y+1
=x^2(x^2-1)-x^2(1-y)+(1-y)
=x^2(x^2-1)-(1-y)(x^2-1)
=(x+1)(x-1)(x^2+y-1)

ax^2+3x^2-4a-12 =x^2(a+3)-4(a+3)=(x+2)(x-2)(a+3) x^2+a^2-bx-ab+2ax=(x+a)^2-b(a+x)=(x+a)(x+a-b) x^2-4x+4-3x+6=(x-2)^2-3(x-2)=(x-2)(x-5) x^4-2x^2+x^2y-y+1=(-x^2+1)+(x^4-x^2)+x^2y-y=-(x-1)（x+1)+x^2(x+1)...