(3x+2y)除以2=(2x+y)除以5=(x-y+1)除以6急将急将急将积极急将急将积极急将急将急将急将积极急

问题描述:

(3x+2y)除以2=(2x+y)除以5=(x-y+1)除以6
急将急将急将积极急将急将积极急将急将急将急将积极急

(3x+2y)除以2=(2x+y)除以5
两边乘10
15x+10y=4x+2y
11x=-8y
y=-11x/8 (1)
(3x+2y)除以2=(x-y+1)除以6
l两边乘6
9x+6y=x-y-1
8x+7y=-1 (2)
(1)代入(2)
8x-77x/8=-1
-13x/8=-1
所以
x=8/13
y=-11x/8=-11/13